A mass of 11.0 kg is suspended from a rigid support by an aluminum wire of length 2.0 m, diameter 2.0 mm and Young’s modulus 7.0 x 10(^{11}) Nm(^{-2}). Determine the extension produced. [g = 10 ms(^{-2}); (pi) = 3.142]
Explanation
E = (frac{Fl}{Ae})
E = 7.0 x 10(^{-11}) Nm(^{-2});
F = mass x acceleration due to gravity
= 11 x 10 = 110N
l = 2.0m
A = (pi) r(^2)
d = 2.0 mm (implies) r = 1.0 mm
A = 3.142 x ((frac{10}{1000})^2)
e = (frac{Fl}{EA} = frac{110 times 20}{7.0 times 10^{11} times 3.142(frac{10}{1000})^2})
= 1.0 x 10(^{-5})m