A man and his wife are both heterozyous for the sickle-cell trait. The likely percentage of their offspring that will be either carriers or sicklers is
-
A.
75% -
B.
50% -
C.
25% -
D.
100%
Correct Answer: Option A
Explanation
An heterozygote for sickle-cell anaemia = AS
Crossing two AS persons, we have one AA, two AS and one SS.
(therefore) The probability that the children are either carriers or sicklers = (frac{3}{4})
= 75%