A load of 5N gives an extension of 0.56cm in a wire which obeys Hooke’s law. What is the extension caused by a load of 20N?
-
A.
1.12cm -
B.
2.14cm -
C.
2.24cm -
D.
2.52cm
Correct Answer: Option C
Explanation
(frac{F_1}{e_1}) = (frac{F_2}{e_2})
(frac{5}{0.56}) = (frac{20}{e_2})
e2 = 2.24cm