A lens of focal length 12.0cm forms an upright image three times the size of a real object. The distance between the object and the images is
-
A.
8.0cm -
B.
16.0cm -
C.
24.0cm -
D.
32.0cm
Correct Answer: Option D
Explanation
F = 12cm, V = 3u
F = (frac{uv}{u + v})
12 = (frac{utimes 3u}{u + 3v})
u = 16cm, and v = 48cm
therefore, distance between u and v
v = 48 – 16 = 32cm