A lamp is rated 240V, 60W. The resistance of the filament is
-
A.
960(Omega) -
B.
16(Omega) -
C.
15(Omega) -
D.
4(Omega)
Correct Answer: Option A
Explanation
P = (frac{V_2}{R}) (Rightarrow) R = (frac{V_2}{p})
= (frac{240times 240}{60})
= 960(Omega)
P = (frac{V_2}{R}) (Rightarrow) R = (frac{V_2}{p})
= (frac{240times 240}{60})
= 960(Omega)