A hydrocarbon has an empirical formula CH and a vapour density of 39. Determine its molecular formula.
[C = 12, H = 1]
[C = 12, H = 1]
-
A.
C2H6 -
B.
C3H8 -
C.
C3H4 -
D.
C6H6
Correct Answer: Option D
Explanation
molecular mass = 2 x vapour density
= 2 x 39 = 79
∴ Cn Hn = 78
12n + 1n = 78
13n = 78
n = (frac{78}{13}) = 6
∴ Cn Hn = C 6H 6