A hydrocarbon contained 14.3% hydrogen. The empirical formula for the hydrocarbon is [H= 1.0, C= 12.0]
-
A.
(CH) -
B.
(CH_{2}) -
C.
(CH_{3}) -
D.
(CH_{4})
Correct Answer: Option B
Explanation
The percentage of Carbon in the compound is (100 – 14.3)% = 85.7%
C : H
(frac{85.7}{12.0} : frac{14.3}{1.0})
( 7.14 : 14.3)
(frac{7.14}{7.14} : frac{14.3}{7.14})
(approxeq 1 : 2)
Therefore, the empirical formula is (CH_{2}).