A galvanometer of resistance 20(Omega) is to be provided with a shunt that (frac{1}{10}) of the whole current in a circuit passes through the galvanometer. The resistance of the shunt is
-
A.
2.00(Omega) -
B.
2.22(Omega) -
C.
18.00(Omega) -
D.
18.22(Omega)
Correct Answer: Option B
Explanation
(frac{1}{10})I x 20 = (frac{9}{10})I x Rs
Rs = 2.22(Omega)