A force of 40 N is applied at the end of a wire 4m long and produces an extension of 0.24mm. If the diameter of the wire is 2.00mm, calculate the;
(i) stress on the wire; (ii) strain in the wire.
Explanation
(i) Stress = (frac{force}{text{cross sectiona area}})
= (frac{40}{3.142 (1 times 10^{-3})^2}) = 12.74 x 10(^{6})Nm(^{-2})
(ii) Strain = (frac{e}{I}) = (frac{24 times 10^{-5}}{4})
= 6.0 x 10(^{-5})