A force of 40 N applied at the end of a wire of length 4m and diameter 2.00 mm produces an extension of 0.24 mm. Calculate the;
(a) stress on the wire;
(b) strain in the wire ((pi = 3.142))
Explanation
Stress = (frac{F}{A} = frac{40}{3.14(1 times 10^{-3})^2} = 12.74 times 10^{6} Nm^{-2})
(b) Strain = (frac{e}{I} = frac{24 times 10^{-5}}{4} = 6 times 10^{-5})