A force of 100N stretches an elastic string to a total length of 20cm. If an additional force of 100N stretches the string 5cm further, Find the natural length of the string
-
A.
15cm -
B.
12cm -
C.
10cm -
D.
8cm -
E.
5cm
Correct Answer: Option A
Explanation
Using, f1 = f2
e1 = 20 – L ; e2 = 5cm
(frac{f_1}{e_1}) = (frac{f_2}{e_2})
(frac{100}{20 – L}) = (frac{100}{5})
hence, L = 15cm