A cube of side 10cm and mass 0.5kg floats in a liquid with only (frac{1}{5}) of its height above the liquid surface. What is the relative density of the liquid?
-
A.
0.125cm-1 -
B.
0.250gcm-1 -
C.
0.625cm-1 -
D.
2.500cm-1
Correct Answer: Option C
Explanation
Height below liquid = 1 – (frac{1}{5}) = (frac{4}{5})
volume of cube = 103cm3
volume of liquid displaced = (frac{4}{5}) x 1000
= 800cm3
density of liquid displaced;
= (frac{500}{800})
= 0.625cm-1