A converging lens of focal length 5cm forms a virtual image which is 10cm from the lens. How far from the lens is the object?
-
A.
2.0cm -
B.
3.3cm -
C.
5.0cm -
D.
10.0cm -
E.
15.0cm
Correct Answer: Option B
Explanation
(f = frac{uv}{u+v})
(5 = frac{-10u}{-10+u})
(50 + 5u = -10u)
(50 = -10u – 5u)
(u = frac{50}{-15})
u= -3.3cm