A constant force of magnitude F acts on an object of mass 0.04kg initially at rest at a point O. if the speed of the object when it has moved 50m from O is 500ms-1, what is the value of F?
-
A.
0.4N -
B.
100.0N -
C.
250.0N -
D.
1000.0N
Correct Answer: Option B
Explanation
F = ma and V2 = U2 + 2aX
F = m(frac{(V^2 – U^2)}{2X})
= 0.04(frac{(500^2 – 0^2)}{2 times 50})
F = 100N