A constant force of 40N acting on a body initially at rest gives an acceleration of 0.1ms-2 for 4s. Calculate the work done by the force
-
A.
8J -
B.
10J -
C.
32J -
D.
160J
Correct Answer: Option C
Explanation
X = ut + (frac{1}{2})at2
= (0 x 4) + ((frac{1}{2}) x 0.1 x 4 x 4)
= 0.8m
workdone = force x distance
= 40 x 0.8
= 32J