A coin is pushed from the edge of a laboratory bench with a horizontal velocity of 15.0 ms-1. If the height of the bench from the floor is 1.5m, calculate the distance from the foot of the bench to the point of impact with the floor [g = 10ms-2]
-
A.
0.75m -
B.
2.25m -
C.
8.22m -
D.
15.00m
Correct Answer: Option C
Explanation
S = U(sqrt{frac{2h}{g}})
= 15(sqrt{frac{2 times 1.5}{10}})
= 8.22m