a chemical cell of internal resistance 1(Omega) supplies electric current to an external resistor of resistance 3(Omega). Calculate the efficiency of the cell
-
A.
75% -
B.
50% -
C.
33% -
D.
25%
Correct Answer: Option A
Explanation
R = (r_1 + R = 1 + 3 = 4Omega)
(frac{3}{4} times frac{100}{1} = 75)%