A charge of 1.0 x 10-5 Coulombs experience force of 40N at a certain point in space. What is the electric field intensity?
-
A.
8.00 x 106NC-1 -
B.
4.00 x 106NC-1 -
C.
4.00 x 10-4NC-1 -
D.
2.00 x 10-4NC-1 -
E.
2.50 x 10-1NC-1
Correct Answer: Option B
Explanation
F = qE; E = F/q = 40/(1.0 x 10-5) = 4.0 x 106