a cell of e.m.f. 1.5V and internal resistance 1.0(Omega) is connected to two resistor of resistance 2.0(Omega) and 3.0(Omega) in series. Calculate the current through the resistors
-
A.
0.25A -
B.
0.30A -
C.
0.35A -
D.
0.50A
Correct Answer: Option A
Explanation
I = (frac{E}{R + r} = frac{1.5}{5 + 1})
= (frac{1.5}{6} = 0.25A)