A cell of e.m.f. 1.5 V and internal resistance of 2.59 is connected in series…

A cell of e.m.f. 1.5 V and internal resistance of 2.59 is connected in series with an ammeter of resistance 0.59 and a resistor of resistance 7.09. Calculate the current in the circuit.
  • A.
    0.15 A
  • B.
    0.20 A
  • C.
    0.60A
  • D.
    3.00A
  • E.
    6.67 A.
Correct Answer: Option A
Explanation
I =

E/R + r

=

1.5/2.5 + 0.5 + 7

= 0.15

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