A body of mass 25kg, moving at 3ms-1 on a rough horizontal floor is at rest after sliding through a distance of 2.50m on the floor. Calculate the co-efficient of sliding friction. [g = 10.0ms-2]
-
A.
0.09 -
B.
0.18 -
C.
0.36 -
D.
0.54
Correct Answer: Option B
Explanation
a = (frac{v^2 – u^2}{2a} = frac{0^2 – 3^2}{2 times 2.5}) = 1.8m/s2
F = ma = 25 x 1.8 = 45N
but (mu = frac{F}{R} = frac{45}{25 times 10} = 0.18)