A body accelerates uniformly from rest at 2(ms^{-2}). Calculate its velocity when it has travelled a distance of 9m.
-
A.
3.0(ms^{-1}) -
B.
4.5(ms^{-1}) -
C.
6.0(ms^{-1}) -
D.
18.0(ms^{-1})
Correct Answer: Option C
Explanation
Given that (u = 0ms^{-1}, a = 2ms^{-2}, s = 9m)
We can use the equation, (v^{2}=u^{2} +2as) so that we have,
(v^{2} = 0^{2} + 2times 2times 9)
(v^{2} = 36; v= 6.0ms^{-1})
Note; u = Initial velocity
v = final velocity
a = acceleration
s = distance covered