A block of wood of density 0.6 gcm(^{-3}), weighing 3.06N in air, floats freely in a liquid of density 0.9 gcm(^{-3}). Calculate volume of the portion immersed (g = 10ms(^{-2}))
-
A.
510cm3 -
B.
340cm3 -
C.
254cm3 -
D.
170cm3
Correct Answer: Option B
Explanation
V = (frac{M}{D})
= (frac{3.06}{10} times frac{1000}{0.9} = 340)