A battery of e.m.f. 12.0V and internal resistance0.5(Omega) is connected to 1.5(Omega) and 4.0(Omega) series resistor. Calculate the terminal voltage of the battery.
-
A.
13.0V -
B.
11.0V -
C.
3.0V -
D.
1.0V
Correct Answer: Option B
Explanation
(frac{V}{R} = frac{E}{R + r} = frac{V}{5.5} = frac{12}{6})
v = 11.0V