A ball is projected specific latent heat of ice = 3.4 x 10(^{2}) Jg(^{-1}) horizontally…

 A ball is projected specific latent heat of ice = 3.4 x 10(^{2}) Jg(^{-1}) horizontally from a height of 20m above the ground specific heat capacity of water = 4.2 Jg(^{-1}) K(^{-1}) with an initial velocity of 0.4ms(^{-1}). Calculate the horizontal distance moved by the ball before hitting the ground. [g = 10ms(^{-1})]

Explanation

R = (Usqrt{frac{2H}{g}})

= 0.4 (sqrt{frac{2 times 20}{10}})

= 0.8m

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