8g CH4 occupies 11.2 dm3 at s.t.p. What volume would 22 g of CH3CH3 occupy under the same condition?
(C = 12, H = 1)
(C = 12, H = 1)
-
A.
3.7 dm3 -
B.
11.2 dm3 -
C.
22.4 dm3 -
D.
33.6 dm3
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