(^{27}_{13}Al) + (^{1}_{0}n) (Rightarrow) (^{24}_{11}Na) + X
-
A.
a proton -
B.
a gamma ray -
C.
a helium particle -
D.
an alpha particle
Correct Answer: Option D
Explanation
(^{27}_{13}Al) + (^{1}_{0}n) (Rightarrow) (^{24}_{11}Na) + (^{b}_{a}X)
a + 11 = 0 + 13 (Rightarrow) a = 2
b + 24 = 1 + 27 (Rightarrow) b = 4
(^{b}_{a}X) = (^{4}_{2}alpha)