20 cm3 of 1.0 molar NH4OH solution when neutralized with 20.05cm3 of 0.1 molar HCl liberated -102 joules of heat. Calculate the heat of neutralization of NH4OH?
-
A.
-51.O KJ mol– -
B.
+57.3 KJ mol– -
C.
+57.O KJ mol– -
D.
+51.0 KJ mol–
Correct Answer: Option A
Explanation
NH4OH = 20cm of 0.1 m
NH4 + HCl → NH4Cl = H2O
Heat of Neutralization of NH4OH
= (frac{-102}{2}) = -51.0 KJ mole-1